Created
January 12, 2014 02:22
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Euler 23 solution, started with shlomif's code and went my own way with it.
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# Adapted by Shlomi Fish. | |
# | |
# Solution for: | |
# | |
# http://projecteuler.net/problem=23 | |
# | |
# A perfect number is a number for which the sum of its proper divisors | |
# is exactly equal to the number. For example, the sum of the proper | |
# divisors of 28 would be 1 + 2 + 4 + 7 + 14 = 28, which means that 28 | |
# is a perfect number. | |
# | |
# A number n is called deficient if the sum of its proper divisors is | |
# less than n and it is called abundant if this sum exceeds n. | |
# | |
# As 12 is the smallest abundant number, 1 + 2 + 3 + 4 + 6 = 16, the | |
# smallest number that can be written as the sum of two abundant numbers | |
# is 24. By mathematical analysis, it can be shown that all integers | |
# greater than 28123 can be written as the sum of two abundant numbers. | |
# However, this upper limit cannot be reduced any further by analysis | |
# even though it is known that the greatest number that cannot be | |
# expressed as the sum of two abundant numbers is less than this limit. | |
# | |
# Find the sum of all the positive integers which cannot be written as | |
# the sum of two abundant numbers. | |
# | |
use v6; | |
my $MAX = 28_123; | |
my @primes = (1..$MAX).grep(*.is-prime); | |
sub prime-factorization(Int $num is copy) { | |
my $factors = BagHash.new; | |
my $pi = 0; | |
while $num > 1 { | |
if $num %% @primes[$pi] { | |
$num div= @primes[$pi]; | |
$factors{@primes[$pi]}++; | |
} else { | |
if $pi < @primes { | |
$pi++; | |
} else { | |
last; | |
} | |
} | |
} | |
$factors; | |
} | |
sub base-whatever-digits($num is copy, @bases) { | |
@bases.map: -> $base { | |
my $digit = $num % $base; | |
$num = ($num - $digit) div $base; | |
$digit; | |
} | |
} | |
sub divisors(Int $num) { | |
my $factors = prime-factorization($num); | |
my @factors = $factors.keys; | |
my @bases = @factors.map({ $factors{$_} + 1 }); | |
(^(([*] @bases) - 1)).map: -> $i { | |
my @bwd = base-whatever-digits($i, @bases); | |
[*] @factors Z** @bwd; | |
} | |
} | |
sub sum-divisors(Int $num) | |
{ | |
[+] divisors($num); | |
} | |
sub is-abundant(Int $num) | |
{ | |
sum-divisors($num) > $num; | |
} | |
my @abundant = (1..$MAX).grep({ is-abundant($_) }); | |
my $abundant-sum-numbers = (@abundant X+ @abundant).grep(* <= $MAX).Set; | |
say "Sum == ", [+] (1..$MAX).grep(* ∉ $abundant-sum-numbers); |
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