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Created July 23, 2014 03:16
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30 行 Python 代码搞定 X 算法
#!/usr/bin/env python3
# Author: Ali Assaf <ali.assaf.mail@gmail.com>
# Copyright: (C) 2010 Ali Assaf
# License: GNU General Public License <http://www.gnu.org/licenses/>
from itertools import product
def solve_sudoku(size, grid):
""" An efficient Sudoku solver using Algorithm X.
>>> grid = [
... [5, 3, 0, 0, 7, 0, 0, 0, 0],
... [6, 0, 0, 1, 9, 5, 0, 0, 0],
... [0, 9, 8, 0, 0, 0, 0, 6, 0],
... [8, 0, 0, 0, 6, 0, 0, 0, 3],
... [4, 0, 0, 8, 0, 3, 0, 0, 1],
... [7, 0, 0, 0, 2, 0, 0, 0, 6],
... [0, 6, 0, 0, 0, 0, 2, 8, 0],
... [0, 0, 0, 4, 1, 9, 0, 0, 5],
... [0, 0, 0, 0, 8, 0, 0, 7, 9]]
>>> for solution in solve_sudoku((3, 3), grid):
... print(*solution, sep='\\n')
[5, 3, 4, 6, 7, 8, 9, 1, 2]
[6, 7, 2, 1, 9, 5, 3, 4, 8]
[1, 9, 8, 3, 4, 2, 5, 6, 7]
[8, 5, 9, 7, 6, 1, 4, 2, 3]
[4, 2, 6, 8, 5, 3, 7, 9, 1]
[7, 1, 3, 9, 2, 4, 8, 5, 6]
[9, 6, 1, 5, 3, 7, 2, 8, 4]
[2, 8, 7, 4, 1, 9, 6, 3, 5]
[3, 4, 5, 2, 8, 6, 1, 7, 9]
"""
R, C = size
N = R * C
X = ([("rc", rc) for rc in product(range(N), range(N))] +
[("rn", rn) for rn in product(range(N), range(1, N + 1))] +
[("cn", cn) for cn in product(range(N), range(1, N + 1))] +
[("bn", bn) for bn in product(range(N), range(1, N + 1))])
Y = dict()
for r, c, n in product(range(N), range(N), range(1, N + 1)):
b = (r // R) * R + (c // C) # Box number
Y[(r, c, n)] = [
("rc", (r, c)),
("rn", (r, n)),
("cn", (c, n)),
("bn", (b, n))]
X, Y = exact_cover(X, Y)
for i, row in enumerate(grid):
for j, n in enumerate(row):
if n:
select(X, Y, (i, j, n))
for solution in solve(X, Y, []):
for (r, c, n) in solution:
grid[r][c] = n
yield grid
def exact_cover(X, Y):
X = {j: set() for j in X}
for i, row in Y.items():
for j in row:
X[j].add(i)
return X, Y
def solve(X, Y, solution):
if not X:
yield list(solution)
else:
c = min(X, key=lambda c: len(X[c]))
for r in list(X[c]):
solution.append(r)
cols = select(X, Y, r)
for s in solve(X, Y, solution):
yield s
deselect(X, Y, r, cols)
solution.pop()
def select(X, Y, r):
cols = []
for j in Y[r]:
for i in X[j]:
for k in Y[i]:
if k != j:
X[k].remove(i)
cols.append(X.pop(j))
return cols
def deselect(X, Y, r, cols):
for j in reversed(Y[r]):
X[j] = cols.pop()
for i in X[j]:
for k in Y[i]:
if k != j:
X[k].add(i)
if __name__ == "__main__":
import doctest
doctest.testmod()
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