How to convert matlab's datenum representation of time to python's datetime representation.

datenum2datetime.py

from datetime import datetime, timedelta

matlab_datenum = 731965.04835648148
python_datetime = datetime.fromordinal(int(matlab_datenum)) + timedelta(days=matlab_datenum%1) - timedelta(days = 366)

Maybe this is simpler:
python_datetime = datetime.timedelta(days=matlab_datenum -366)+datetime.datetime(1,1,1)

Cross referencing the gist to its matching blog post: https://sociograph.blogspot.com/2011/04/how-to-avoid-gotcha-when-converting.html

I have tried the suggestion by conradlee and wjwxxn, but they both do not work for an array of precise ordinal times (e.g. times like 731965.04835648148 in an array).

daluu, the link you gave goes to a blog, which has a comment to come here, which was also a redirection from another post ... the solutions trail is circular, and nothing seems to be working with an array of ordinal times in decimals.