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def set_value(ary, index: int) -> int: | |
if index < len(ary): | |
return ary[index] | |
else: | |
return None | |
def array_sum(ary) -> int: | |
if len(ary) == 0: | |
return 0 | |
curr_index = 0 | |
current_sum, prev_sum = ary[curr_index], 0 | |
slow_iter = curr_index + 3 | |
fast_iter = curr_index + 4 | |
current_val, slow_val, fast_val = 0, 0, 0 | |
while (curr_index < len(ary)): | |
prev_sum = current_sum | |
current_val = ary[curr_index] | |
# look ahead and set our +3 val | |
slow_val = set_value(ary=ary, index=(curr_index + 3)) | |
fast_val = set_value(ary=ary, index=(curr_index + 4)) | |
# if we are out of bounds on both iters, break out. | |
if not slow_val and not fast_val: | |
break | |
# slow will never be None while fast has a value. So check for the | |
# possibility that fast is None. Our previous check above | |
# will catch the possibility of both being None. | |
if not fast_val: | |
current_sum += slow_val | |
curr_index = curr_index + 3 | |
elif slow_val >= fast_val: | |
current_sum += slow_val | |
curr_index = curr_index + 3 | |
elif fast_val > slow_val: | |
current_sum += fast_val | |
curr_index = curr_index + 4 | |
# If we have a value that is best case between slow and fast values | |
# is less than our previous. We can exit as per requirements. | |
if prev_sum > current_sum: | |
break; | |
return max(prev_sum, current_sum) | |
test_input_1 = [scrubbed] | |
print(array_sum(ary=test_input_1)) | |
> 140 | |
test_input_2 = [scrubbed] | |
print(array_sum(ary=test_input_2)) | |
> 458 |
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