Skip to content

Instantly share code, notes, and snippets.

@cosenary

cosenary/index.php

Last active June 17, 2019 15:04
Show Gist options
  • Star 10 You must be signed in to star a gist
  • Fork 7 You must be signed in to fork a gist
  • Save cosenary/8803601 to your computer and use it in GitHub Desktop.
Save cosenary/8803601 to your computer and use it in GitHub Desktop.
Download ZIP
Instagram API login (with sessions)
Raw
index.php
<?php
require '../src/Instagram.php';
use MetzWeb\Instagram\Instagram;
session_start();
if (isset($_SESSION['access_token'])) {
// user authentication -> redirect to media
header('Location: success.php');
}
// initialize class
$instagram = new Instagram(array(
'apiKey' => 'YOUR_APP_KEY',
'apiSecret' => 'YOUR_APP_SECRET',
'apiCallback' => 'YOUR_APP_CALLBACK'
));
// create login URL
$loginUrl = $instagram->getLoginUrl(array(
'basic',
'likes',
'relationships'
));
?>
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>Instagram - OAuth Login</title>
<link rel="stylesheet" type="text/css" href="assets/style.css">
<style>
.login {
display: block;
font-size: 20px;
font-weight: bold;
margin-top: 50px;
}
</style>
</head>
<body>
<div class="container">
<header class="clearfix">
<h1>Instagram <span>display your photo stream</span></h1>
</header>
<div class="main">
<ul class="grid">
<li><img src="assets/instagram-big.png" alt="Instagram logo"></li>
<li>
<a class="login" href="<?php echo $loginUrl ?>">» Login with Instagram</a>
<h4>Use your Instagram account to login.</h4>
</li>
</ul>
<!-- GitHub project -->
<footer>
<p>created by <a href="https://github.com/cosenary/Instagram-PHP-API">cosenary's Instagram class</a>, available on GitHub</p>
</footer>
</div>
</div>
</body>
</html>
Raw
success.php
<?php
/**
* Instagram PHP API
*
* @link https://github.com/cosenary/Instagram-PHP-API
* @author Christian Metz
*/
require '../src/Instagram.php';
use MetzWeb\Instagram\Instagram;
// initialize class
$instagram = new Instagram(array(
'apiKey' => 'YOUR_APP_KEY',
'apiSecret' => 'YOUR_APP_SECRET',
'apiCallback' => 'YOUR_APP_CALLBACK'
));
session_start();
$token = false;
if (isset($_SESSION['access_token'])) {
// user authenticated -> receive and set token
$token = $_SESSION['access_token'];
} else {
// receive OAuth code parameter
$code = $_GET['code'];
// authentication in progress?
if (isset($code)) {
// receive and store OAuth token
$data = $instagram->getOAuthToken($code);
$token = $data->access_token;
$_SESSION['access_token'] = $token;
} else {
// check whether an error occurred
if (isset($_GET['error'])) {
echo 'An error occurred: ' . $_GET['error_description'];
}
}
}
// check authentication
if ($token === false) {
// authentication failed -> redirect to login
header('Location: index.php');
} else {
// store user access token
$instagram->setAccessToken($token);
// now we have access to all authenticated user methods
$media = $instagram->getUserMedia();
}
?>
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<title>Instagram - photo stream</title>
<link href="https://vjs.zencdn.net/4.2/video-js.css" rel="stylesheet">
<link href="assets/style.css" rel="stylesheet">
<script src="https://vjs.zencdn.net/4.2/video.js"></script>
</head>
<body>
<div class="container">
<header class="clearfix">
<img src="assets/instagram.png" alt="Instagram logo">
<h1>Instagram photos <span>taken by <?php echo $data->user->username ?></span></h1>
</header>
<div class="main">
<ul class="grid">
<?php
// display all user likes
foreach ($result->data as $media) {
$content = "<li>";
// output media
if ($media->type === 'video') {
// video
$poster = $media->images->low_resolution->url;
$source = $media->videos->standard_resolution->url;
$content .= "<video class=\"media video-js vjs-default-skin\" width=\"250\" height=\"250\" poster=\"{$poster}\"
data-setup='{\"controls\":true, \"preload\": \"auto\"}'>
<source src=\"{$source}\" type=\"video/mp4\" />
</video>";
} else {
// image
$image = $media->images->low_resolution->url;
$content .= "<img class=\"media\" src=\"{$image}\"/>";
}
// create meta section
$avatar = $media->user->profile_picture;
$username = $media->user->username;
$comment = $media->caption->text;
$content .= "<div class=\"content\">
<div class=\"avatar\" style=\"background-image: url({$avatar})\"></div>
<p>{$username}</p>
<div class=\"comment\">{$comment}</div>
</div>";
// output media
echo $content . "</li>";
}
?>
</ul>
<!-- GitHub project -->
<footer>
<p>created by <a href="https://github.com/cosenary/Instagram-PHP-API">cosenary's Instagram class</a>, available on GitHub</p>
<iframe width="95px" scrolling="0" height="20px" frameborder="0" allowtransparency="true" src="http://ghbtns.com/github-btn.html?user=cosenary&repo=Instagram-PHP-API&type=fork&count=true"></iframe>
</footer>
</div>
</div>
<!-- javascript -->
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<script>
$(document).ready(function() {
// rollover effect
$('li').hover(
function() {
var $media = $(this).find('.media');
var height = $media.height();
$media.stop().animate({ marginTop: -(height - 82) }, 1000);
}, function() {
var $media = $(this).find('.media');
$media.stop().animate({ marginTop: '0px' }, 1000);
}
);
});
</script>
</body>
</html>
@integrap
Copy link

Invalid argument supplied for foreach() xxx.com/success.php on line 69
Can you help me about this issue?

@mustafakucuk
Copy link

$media variable in 55. line need be $result

@Hamroyev
Copy link

where instagram.php file?

Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment