Split a list into n list containing an even number of element

splitIn.scala

  /** Split a list in n List */
  def splitIn[A](n: Int)(l: List[A]): List[List[A]] = {
    l.zipWithIndex
      .foldLeft(Array.fill(n)(List.empty[A])) {
        case (b, a) =>
          b(a._2 % n) = a._1 :: b(a._2 % n)
          b
      }
      .filter(_.nonEmpty)
      .map(_.reverse)(collection.breakOut)
  }