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@creotiv
Created September 13, 2012 11:51
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Getting coordinates without gps by cell phone
country = 'fr'
device = "Nokia N95 8Gb"
user_agent = 'Mozilla/4.0 (compatible; MSIE 5.5; Windows NT)'
mmap_url = 'http://www.google.com/glm/mmap'
geo_url = 'http://maps.google.com/maps/geo'
from struct import pack, unpack
from httplib import HTTP
import urllib2
def fetch_latlong_http(query):
http = HTTP('www.google.com', 80)
http.putrequest('POST', '/glm/mmap')
http.putheader('Content-Type', 'application/binary')
http.putheader('Content-Length', str(len(query)))
http.endheaders()
http.send(query)
code, msg, headers = http.getreply()
result = http.file.read()
return result
def fetch_latlong_urllib(query):
headers = { 'User-Agent' : user_agent }
req = urllib2.Request(mmap_url, query, headers)
resp = urllib2.urlopen(req)
response = resp.read()
return response
fetch_latlong = fetch_latlong_http
def get_location_by_cell(cid, lac, mnc=0, mcc=0, country='fr'):
b_string = pack('>hqh2sh13sh5sh3sBiiihiiiiii',
21, 0,
len(country), country,
len(device), device,
len('1.3.1'), "1.3.1",
len('Web'), "Web",
27, 0, 0,
3, 0, cid, lac,
0, 0, 0, 0)
bytes = fetch_latlong(b_string)
(a, b,errorCode, latitude, longitude, c, d, e) = unpack(">hBiiiiih",bytes)
latitude = latitude / 1000000.0
longitude = longitude / 1000000.0
return latitude, longitude
def get_location_by_geo(latitude, longitude):
url = '%s?q=%s,%s&output=json&oe=utf8' % (geo_url, str(latitude), str(longitude))
return urllib2.urlopen(url).read()
if __name__ == '__main__':
print i,get_location_by_cell(20465, 495, 3, 262)
print get_location_by_cell(20442, 6015)
print get_location_by_cell(1085, 24040)
print get_location_by_geo(40.714224, -73.961452)
print get_location_by_geo(13.749113, 100.565327)
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