Spawning a childprocess in node.js

spawn.js

var spawn = require('child_process').spawn;

var proc = spawn('/path/to/executable', ['param1', 'param2', 'param3']);

var self = {
  _stdoutBuf: '',
  _stderrBuf: ''
};

proc.stdout.on('data', function(data) {
  var buf = self._stdoutBuf;
  buf += data;
  var newline;
  while ((newline = buf.indexOf('\n')) > -1) {
    var response = buf.slice(0, newline);
    buf = buf.slice(newline+1);
    //response = JSON.parse(response);
    console.log('STDOUT: ' + response);
  }
  self._stdoutBuf = buf;
});

proc.stderr.on('data', function(data) {
  var buf = self._stderrBuf;
  buf += data;
  var newline;
  while ((newline = buf.indexOf('\n')) > -1) {
    var response = buf.slice(0, newline);
    buf = buf.slice(newline+1);
    //response = JSON.parse(response);
    console.log('STDERR: ' + response);
  }
  self._stderrBuf = buf;
});

proc.on('exit', function(code) {
  console.log(' => Child process exited with code ' + code);
});