Created
September 2, 2015 20:08
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yukicoder No.66
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#include <iostream> | |
#include <iomanip> | |
#include <vector> | |
#include <algorithm> | |
#include <numeric> | |
#include <functional> | |
#include <cmath> | |
#include <queue> | |
#include <stack> | |
#define repd(i,a,b) for (int i=(a);i<(b);i++) | |
#define rep(i,n) repd(i,0,n) | |
#define NUM 1100 | |
typedef long long ll; | |
using namespace std; | |
int inputValue(){ | |
int a; | |
cin >> a; | |
return a; | |
}; | |
void inputArray(int * p, int a){ | |
rep(i, a){ | |
cin >> p[i]; | |
} | |
}; | |
void inputVector(vector<int> * p, int a){ | |
rep(i, a){ | |
int input; | |
cin >> input; | |
p -> push_back(input); | |
} | |
} | |
template <typename T> | |
void output(T a, int precision) { | |
if(precision > 0){ | |
cout << setprecision(precision) << a << "\n"; | |
} | |
else{ | |
cout << a << "\n"; | |
} | |
} | |
int power(int n, int m){ | |
int ret = 1; | |
rep(i, m){ | |
ret *= n; | |
} | |
return ret; | |
} | |
// a = 01011, b = 01000 d = 5 -> ret = d - 3 = 1 | |
int digit(int a, int b, int d){ | |
int num = 0; | |
int c = 1 << (d - 1); | |
rep(i, d){ | |
if ((c & a) == (c & b)) { | |
c = c >> 1; | |
num++; | |
} | |
else{ | |
break; | |
} | |
} | |
return d - num; | |
} | |
double P[NUM] = {0}; | |
double dp[NUM][11] = {1}; | |
int main(int argc, const char * argv[]) { | |
// source code | |
int M = inputValue(); | |
int N = power(2,M); | |
rep(i, N){ | |
cin >> P[i]; | |
} | |
rep(i, N){ | |
dp[i][0] = 1; | |
} | |
repd(i, 1, M + 1){ | |
rep(j, N){ | |
double temp = 0.0; | |
rep(k, N){ | |
if (digit(j, k, M) == i && j != k) { | |
temp += dp[k][i - 1] * P[j] * P[j] / (P[j] * P[j] + P[k] * P[k]); | |
} | |
} | |
dp[j][i] = dp[j][i - 1] * temp; | |
} | |
} | |
output(dp[0][M], 10); | |
return 0; | |
} |
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