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August 29, 2015 13:57
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An idea regarding back-pressure for iterable sources.
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var Rx = require('rx'), | |
Ix = require('ix'), | |
log = console.log.bind(console); | |
Rx.Observable.iterate( | |
Ix.Enumerable.range(0, 100), | |
10, | |
function (x) { | |
return Rx.Observable.empty().delay(Math.random() * 1000); | |
}) | |
.subscribe(log); |
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Rx.Observable.iterate = function (enumerable, maxConcurrent, workSelector) { | |
return Rx.Observable.create(function (o) { | |
var i = 0, | |
items = [], | |
enumerator = enumerable.getEnumerator(), | |
done = new Rx.Subject(), | |
more = function () { | |
if (enumerator.moveNext()) { | |
return true; | |
} else { | |
done.onNext(true); | |
done.onCompleted(); | |
return false; | |
} | |
}, | |
next = Rx.Observable | |
.if( | |
function () { return more(); }, | |
Rx.Observable | |
.defer(function () { | |
return Rx.Observable.return(enumerator.getCurrent()); | |
}) | |
); | |
maxConcurrent || (maxConcurrent = 1); | |
while (i++ < maxConcurrent && more()) { | |
items.push(enumerator.getCurrent()); | |
} | |
return Rx.Observable | |
.fromArray(items) | |
.expand(function (item) { | |
return workSelector(item) | |
.ignoreElements() | |
.concat(next); | |
}) | |
.takeUntil(done) | |
.subscribe(o); | |
}); | |
}; |
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