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Simple vertical d3.js tree diagram
license: mit

This is a simple d3.js tree diagram, arranged so that the tree is vertical, as used as an example in the book D3 Tips and Tricks.

It is derived from the Mike Bostock Collapsible tree example but it is a VERY cut down version without the ability to update (collapse).

<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<title>Collapsible Tree Example</title>
<style>
.node circle {
fill: #fff;
stroke: steelblue;
stroke-width: 3px;
}
.node text { font: 12px sans-serif; }
.link {
fill: none;
stroke: #ccc;
stroke-width: 2px;
}
</style>
</head>
<body>
<!-- load the d3.js library -->
<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/3.5.17/d3.min.js"></script>
<script>
var treeData = [
{
"name": "Top Level",
"parent": "null",
"children": [
{
"name": "Level 2: A",
"parent": "Top Level",
"children": [
{
"name": "Son of A",
"parent": "Level 2: A"
},
{
"name": "Daughter of A",
"parent": "Level 2: A"
}
]
},
{
"name": "Level 2: B",
"parent": "Top Level"
}
]
}
];
// ************** Generate the tree diagram *****************
var margin = {top: 40, right: 120, bottom: 20, left: 120},
width = 960 - margin.right - margin.left,
height = 500 - margin.top - margin.bottom;
var i = 0;
var tree = d3.layout.tree()
.size([height, width]);
var diagonal = d3.svg.diagonal()
.projection(function(d) { return [d.x, d.y]; });
var svg = d3.select("body").append("svg")
.attr("width", width + margin.right + margin.left)
.attr("height", height + margin.top + margin.bottom)
.append("g")
.attr("transform", "translate(" + margin.left + "," + margin.top + ")");
root = treeData[0];
update(root);
function update(source) {
// Compute the new tree layout.
var nodes = tree.nodes(root).reverse(),
links = tree.links(nodes);
// Normalize for fixed-depth.
nodes.forEach(function(d) { d.y = d.depth * 100; });
// Declare the nodes…
var node = svg.selectAll("g.node")
.data(nodes, function(d) { return d.id || (d.id = ++i); });
// Enter the nodes.
var nodeEnter = node.enter().append("g")
.attr("class", "node")
.attr("transform", function(d) {
return "translate(" + d.x + "," + d.y + ")"; });
nodeEnter.append("circle")
.attr("r", 10)
.style("fill", "#fff");
nodeEnter.append("text")
.attr("y", function(d) {
return d.children || d._children ? -18 : 18; })
.attr("dy", ".35em")
.attr("text-anchor", "middle")
.text(function(d) { return d.name; })
.style("fill-opacity", 1);
// Declare the links…
var link = svg.selectAll("path.link")
.data(links, function(d) { return d.target.id; });
// Enter the links.
link.enter().insert("path", "g")
.attr("class", "link")
.attr("d", diagonal);
}
</script>
</body>
</html>
@pfried
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pfried commented Jun 14, 2015

There is an error in the constructor of the tree layout var tree = d3.layout.tree().size([height, width]); The width and height properties are in the wrong order. Should be var tree = d3.layout.tree().size([width, height]);

@bcardiff
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Small tiny thing, the source argument in the update is never used, the root is accessed directly.

Thanks for the sample, it was really helpful.

Edit: And the parent name is not needed on every child. The d3 tree layout override it with a whole reference of the parent node.

@shahidkarimi
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Why its difficult to convert a d3 chart into vertical?

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