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| <VirtualHost *> | |
| ServerName example.com | |
| WSGIDaemonProcess www user=max group=max threads=5 | |
| WSGIScriptAlias / /home/max/Projekte/flask-upload/flask-upload.wsgi | |
| <Directory /home/max/Projekte/flask-upload> | |
| WSGIProcessGroup www | |
| WSGIApplicationGroup %{GLOBAL} | |
| Order deny,allow | |
| Allow from all | |
| </Directory> | |
| </VirtualHost> |
| activate_this = '/home/max/.virtualenvs/flask/bin/activate_this.py' | |
| execfile(activate_this, dict(__file__=activate_this)) | |
| import sys | |
| sys.path.insert(0, '/home/max/Projekte/flask-upload') | |
| from server import app as application |
| import os | |
| from flask import Flask, request, redirect, url_for | |
| from werkzeug import secure_filename | |
| UPLOAD_FOLDER = '/tmp/' | |
| ALLOWED_EXTENSIONS = set(['txt']) | |
| app = Flask(__name__) | |
| app.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER | |
| def allowed_file(filename): | |
| return '.' in filename and \ | |
| filename.rsplit('.', 1)[1] in ALLOWED_EXTENSIONS | |
| @app.route("/", methods=['GET', 'POST']) | |
| def index(): | |
| if request.method == 'POST': | |
| file = request.files['file'] | |
| if file and allowed_file(file.filename): | |
| filename = secure_filename(file.filename) | |
| file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename)) | |
| return redirect(url_for('index')) | |
| return """ | |
| <!doctype html> | |
| <title>Upload new File</title> | |
| <h1>Upload new File</h1> | |
| <form action="" method=post enctype=multipart/form-data> | |
| <p><input type=file name=file> | |
| <input type=submit value=Upload> | |
| </form> | |
| <p>%s</p> | |
| """ % "<br>".join(os.listdir(app.config['UPLOAD_FOLDER'],)) | |
| if __name__ == "__main__": | |
| app.run(host='0.0.0.0', port=5001, debug=True) |
Ty @dAnjou
Thanks!
Thanks
Extremely awesome. Thanks a bunch.
I fellow your code ,when I upload file is normal but I can not found the file in dir
How do you get form data? When I add a line like this:
item_name = request.form['name']
flask throws a 400
@mrmagcore I was able to get the form data by putting name='name' in the html form, as opposed to id='name'. In flask, I was able to access the POST data via name = request.form.getlist('name')
Thanks! A coding style suggestion: could you change the pattern:
if allowed_filename(...):
# code
To:
if not allowed_filename(...):
return error
# code goes unindented here
thanks a lot, having a hard time to do this
fanks you!
What if we want to rename a file if it allreade exists ;), here is How
import os
from flask import Flask, request, redirect, url_for
from werkzeug import secure_filename
UPLOAD_FOLDER = '/tmp/'
ALLOWED_EXTENSIONS = set(['txt'])
app = Flask(name)
app.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER
def allowed_file(filename):
return '.' in filename and
filename.rsplit('.', 1)[1] in ALLOWED_EXTENSIONS
def filenamechanger(filename):
if os.path.isfile(os.path.join(app.config['UPLOAD_FOLDER'], filename)):
myfilename = filename.split('.')
if len(myfilename[0].split(''))>2:
a = myfilename[0].split('')
a.pop()
b = []
for xk in range(0,len(a)):
if xk < len(a)-1:
b.append(''.join([a[xk],'']))
else:
b.append(a[xk])
myfilename[0] = ''.join(b)
print(myfilename)
i = 0
sexer = filename
while os.path.isfile(os.path.join(app.config['UPLOAD_FOLDER'], sexer)):
sexer = ''.join([myfilename[0],'',str(i),'.',myfilename[1]])
print(sexer)
i+= 1
filename = sexer
return filename
return filename
@app.route("/", methods=['GET', 'POST'])
def index():
if request.method == 'POST':
file = request.files['file']
if file and allowed_file(file.filename):
filename = secure_filename(file.filename)
filename = filenamechanger(filename)
file.save(os.path.join(app.config['UPLOAD_FOLDER'],filename))
print('My Filename: ',filename)
return redirect(url_for('index'))
return """
<!doctype html> <title>Upload new File</title> <h1>Upload new File</h1> <form action="" method=post enctype=multipart/form-data> <p><input type=file name=file> <input type=submit value=Upload> </form> <p>%s</p>""" %<br> "".join(os.listdir(app.config['UPLOAD_FOLDER'],))
if name == 'main':
app.run(
host="0.0.0.0",
port=int("80"),
debug=True
)
THANK YOU!
thanks! @dAnjou