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Last active Aug 28, 2015
What would you like to do?
; xs = '{a {p 1, q 2} b {m 3, n 4}}
(for [[x y] xs]
(for [[a b] y]
[[a x] b]))
; this produces
; (({[a p] 1} {[a q] 2}) ({[b m] 3} {[b n] 4}))
; I require
; '{[a p] 1, [a q] 2 [b m] 3, [b n] 4}
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