Complete the findNextSquare method that finds the next integral perfect square after the one passed as a parameter. Recall that an integral perfect square is an integer n such that sqrt(n) is also an integer. If the parameter is itself not a perfect square then -1 should be returned. You may assume the parameter is non-negative.

find_next_square.py

# import math
# def find_next_square(sq):
#     # Return the next square if sq is a square, -1 otherwise
#     if sq % math.sqrt(sq) == 0:
#         sq_number = math.sqrt(sq)
#         new_sq_sq = (sq_number + 1)**2
#         if new_sq_sq % math.sqrt(new_sq_sq) == 0:
#             return new_sq_sq
#         else:
#             return -1
#     else:
#         return -1

def find_next_square(sq):
    root = sq ** 0.5
    if root.is_integer():
        return (root + 1) ** 2
    return -1