Dart - how to create a url with query params with language features

build.dart

// Use language features to build the url
String buildUrlWithQueryParams(String url, Map<String, dynamic> queryParams) {
    final uri = Uri.parse(url);

    final fullUri = uri.replace(
      queryParameters: {
        ...uri.queryParameters,
        ...queryParams,
      },
    );

    final parsedUrl = fullUri.toString();

    if (parsedUrl[parsedUrl.length - 1] == '?') {
      return parsedUrl.substring(0, parsedUrl.length - 1);
    } else {
      return parsedUrl;
    }
  }

void main() {
  final url = buildUrlWithQueryParams("www.google.com?name=ok%C3%BCn-living-cancun", {'param': 'value'});
  print(url); // www.google.com?name=ok%C3%BCn-living-cancun&param=value

}