Created
February 6, 2023 22:00
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photochemistry
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import numpy as np | |
from numpy import pi as π | |
K_1 = 1e-2 | |
k_2 = 1e5 | |
k_3 = 1e-16 | |
t_d = 24 * 60 * 60 | |
def f(c, t): | |
k_1 = K_1 * max(0, np.sin(2 * π * t / t_d)) | |
return np.array( | |
[ | |
k_1 * c[2] - k_2 * c[0], | |
k_1 * c[2] - k_3 * c[1] * c[3], | |
k_3 * c[1] * c[3] - k_1 * c[2], | |
k_2 * c[0] - k_3 * c[1] * c[3], | |
], | |
) | |
def df(c, t): | |
k_1 = K_1 * max(0, np.sin(2 * π * t / t_d)) | |
return np.array( | |
[ | |
[-k_2, 0, +k_1, 0 ], | |
[0, -k_3 * c[3], +k_1, -k_3 * c[1]], | |
[0, +k_3 * c[3], -k_1, +k_3 * c[1]], | |
[+k_2, -k_3 * c[3], 0, -k_3 * c[1]], | |
], | |
) | |
def solve(c_0, dt, num_steps): | |
c = np.zeros((num_steps + 1, len(c_0))) | |
c[0] = c_0 | |
I = np.identity(len(c_0)) | |
for n in range(num_steps): | |
t = n * dt | |
A = I - dt * df(c[n], t) | |
dc_dt = np.linalg.solve(A, f(c[n], t)) | |
c[n + 1] = c[n] + dt * dc_dt | |
return c |
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