Script to download and display the Urban Dictionary word of the day. Used Feedparser to process the RSS feed - see https://code.google.com/p/feedparser for source).

UrbanDictWOTD.py

# Simple script to get the Urban Dictionary Word of the Day via RSS
# Code is released under MIT license. Please see http://opensource.org/licenses/MIT for full license
import feedparser # 3rd party: https://code.google.com/p/feedparser/
from HTMLParser import HTMLParser # Python stdlib
import os

class HTMLStripper(HTMLParser, object):
    def __init__(self):
        HTMLParser.__init__(self)
        self.html = ''

    def handle_data(self, d):
        self.html += str(d.lstrip()) # Python should 'special case' this, resulting in O(n) complexity :)

    def get_processed(self):
        return self.html

def get_word_of_the_day():
    try:
        feed = feedparser.parse('http://feeds.urbandictionary.com/UrbanWordOfTheDay')
        hstrip = HTMLStripper()
    
        if (len(feed.entries) > 0):
            desc = feed.entries[0].description # Only interested in most recent entry
            desc = desc.replace('<br>', os.linesep)
            desc = desc.replace('<br />', os.linesep)
            hstrip.feed(desc)
            print('\"' + feed.entries[0].title + '\"' + os.linesep + hstrip.get_processed())
        else:
            print('No WOTD entries were present in the RSS feed.')
    except:
        print('Something went wrong connecting to the WOTD RSS feed.')

if __name__ == "__main__":
    get_word_of_the_day()