Created
June 29, 2018 14:09
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Conditional Akka Stream Flow
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import akka._ | |
import akka.stream._ | |
import akka.stream.scaladsl._ | |
import akka.actor._ | |
// WARNING: Ordering is not guaranteed. | |
// The problem with this Graph is that when splitting the flow | |
// we obtain 2 concurrent flows. | |
// The result of conditionalFlow can returns after another messages is processed in the brodcast. | |
// ie. If you have 10 messages from 0 to 9. Let's say that we run a conditional flow only for element 0. | |
// It is possible that in output we will get 1,2,3,4,5,6,7,8,9,0 (0 will be returned at the end due to the additional flow execution). | |
// See also: http://grokbase.com/t/gg/akka-user/15bs0vtyt3/akka-stream-will-broadcast-merge-keep-the-message-order | |
// fiddle: https://scalafiddle.io/sf/3yInf1c/6 | |
object ConditionalFlow { | |
def apply[M]( | |
condition: M => Boolean, | |
conditionalFlow: Flow[M, M, NotUsed]): Graph[FlowShape[M, M], NotUsed] = { | |
Flow.fromGraph(GraphDSL.create() { | |
implicit builder => { | |
import GraphDSL.Implicits._ | |
val bcast = builder.add(Broadcast[M](2)) | |
val merge = builder.add(Merge[M](2)) | |
val filter0 = Flow[M].filter(condition) | |
val filter1 = Flow[M].filter(m => !condition(m)) | |
bcast.out(0) ~> filter0 ~> conditionalFlow ~> merge.in(0) | |
bcast.out(1) ~> filter1 ~> merge.in(1) | |
FlowShape(bcast.in, merge.out) | |
} | |
}) | |
} | |
} | |
implicit val system = ActorSystem("Sys") | |
implicit val materializer = ActorMaterializer() | |
def factorial(n: Int): Int = n match { | |
case 0 => 1 | |
case _ => n * factorial(n-1) | |
} | |
Source(List("a", "b", "c")) | |
.via(ConditionalFlow[String]( | |
m => m == "b", | |
Flow[String].map(m => m + factorial(5).toString) | |
)).runWith(Sink.foreach(println)) |
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Thank you! We are using it with a few improvements which do not filter same flow twice: