Source : http://stackoverflow.com/questions/17387222/how-can-i-get-the-names-of-missing-arguments-in-a-javascript-function

argumentValidation

function fnDrawPrism(length, numWidth, intHeight){
    //If any of these parameters are undefined, throw an error that lists the missing parameters.
    // you can cut-and-past the declaration line to fill out 90% of the validation call:
    validate(fnDrawPrism, length, numWidth, intHeight); 

    return length * numWidth * intHeight;
}

// this is cut-and-pasted into a file somewhere, edit to add more types or stricter checking
function validate(args){
    var fn = args, actuals = [].slice.call(arguments, 1),
        hung = {int: "Number", num: "Number", str: "String", arr: "Array",
        obj: "Object", inp: "HTMLInputElement", dt: "Date", bln: "Boolean",
        rx: "RegExp", frm: "HTMLFormElement", doc: "HTMLDocument"},
        names = String(fn).split(/\s*\)\s*/)[0].split(/\s*\(\s*/)[1].split(/\s*\,\s*/),
        mx = names.length, i = 0;
    if(!fn.name)
        fn.name = String(fn).split(/\s*(/)[0].split(/\s+/)[1] || 'anon';
    for(i; i < mx; i++){
        if(actuals[i] === undefined)
            throw new TypeError("missing arg #" + i + " in " + fn.name + " - " + names[i]);
        var hint = hung[names[i].split(/[A-Z]/)[0]],
            got = toString.call(actuals[i]).split(/\W/)[2];
        if(hint && got !== hint)
            throw new TypeError("Wrong type in argument #" + i + " of " + fn.name + " - " + names[i] + ". Got: " + got + ", Expected: " + hint);
}

//try it out:
fnDrawPrism(1);       //! missing arg #1 in fnDrawPrism - numWidth
fnDrawPrism(1,4);     //! missing arg #2 in fnDrawPrism - intHeight
fnDrawPrism(1,2,3);   // ok
fnDrawPrism(1,"2",3); //! Wrong type in argument #1 of fnDrawPrism - numWidth. Got: string, Expected: number