I tackled the Valid Sudoku problem today and it was a fun challenge. The goal is to determine if a given Sudoku board is valid, meaning no row, column, or 3x3 box contains the same number more than once. It's interesting because it requires a combination of logic and algorithmic thinking to solve efficiently.
To solve this problem, I chose a straightforward approach: iterate through the board and keep track of the numbers we've seen so far in each row, column, and box. I used three 2D vectors, row, col, and box, to store this information. The key insight here is to use the fact that the Sudoku board is divided into 3x3 boxes, and we can calculate the index of the box for each cell using the formula (i / 3) * 3 + j / 3.
class Solution {