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@ddre54
Last active December 13, 2020 16:23
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Remove all the keys from redis matching a pattern
--Starting with redis 2.6.0, you can run lua scripts
EVAL "return redis.call('del', unpack(redis.call('keys', ARGV[1])))" 0 prefix:*
--For big number of keys
EVAL "local keys = redis.call('keys', ARGV[1]) \n for i=1,#keys,5000 do \n redis.call('del', unpack(keys, i, math.min(i+4999, #keys))) \n end \n return keys" 0 prefix:*
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