ASP.Net Core Upload Multiple Files , Zip and Save as a byte array in database

FileUpload.cs

using System;
using System.Collections.Generic;
using System.Linq;
using System.Threading.Tasks;
using Microsoft.AspNetCore.Http;
using System.IO;
using System.IO.Compression;

namespace MyNameSpace
{
    public static class FileUpload
    {
        public static byte[] ToZip(List<IFormFile> files)
        {
            long size = files.Sum(f => f.Length);

            // full path to file in temp location: var filePath = Path.GetTempFileName();
            var tempPath = Path.GetTempPath();
            var filePath = tempPath + "/submission/";
            var archiveFile = tempPath + "/zip/archive.zip";
            var archivePath = tempPath + "/zip/";
            if (Directory.Exists(filePath))
            {
                Directory.Delete(filePath, true);
            }
            if (Directory.Exists(archivePath))
            {
                Directory.Delete(archivePath, true);
            }

            Directory.CreateDirectory(filePath);
            Directory.CreateDirectory(archivePath);

            foreach (var formFile in files)
            {
                var fileName = filePath + formFile.FileName;
                if (formFile.Length > 0)
                {
                    using (var stream = new FileStream(fileName, FileMode.Create))
                    {
                        formFile.CopyToAsync(stream);
                    }
                }
            }
            ZipFile.CreateFromDirectory(filePath, archiveFile);
            /* beapen: 2017/07/24
             * 
             * Currently A Filestream cannot be directly converted to a byte array.
             * Hence it is copied to a memory stream before serializing it.
             * This may change in the future and may require refactoring.
             * 
             */
            var stream2 = new FileStream(archiveFile, FileMode.Open);
            var memoryStream = new MemoryStream();
            stream2.CopyTo(memoryStream);
            using (memoryStream)
            {
                return memoryStream.ToArray();
            }
        }
    }
}