gistfile1.txt

/*If we list all the natural numbers below 10 that are multiples of 3 or
 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000.*/



#include <stdio.h>

int main(int argc, char **argv)
{
	int i = 3;
	int max = 1000;

	int max_value = max - 1;

	int total = 0;

	while (i <= max_value)
	{
		if ((i % 3 == 0) || (i % 5 ==0))
		{
			total += i;
		}
		i++;
	}
	printf("%d", total);

	return 0;
}