A simple script which converts decimal number to 8 bit binary code

binary_to_decimal.py

"""
To run:
- Download this code as .py
- Install python3 on your machine
- Open your CMD(Windows) or Terminal in Linux/MacOS and use the following command
  python3 /Path/to/binary_to_decimal.py [COMMAND] [DECIMAL_NUMBER]
  
- COMMANDS
* -b : To convert decimal to binary
* -d : To convert binary to decimal
  
Milestone
- Convert decimal number to bits *
- Convert binary to decimal number *
- Handle signed bytes
  
Note:
This code will fail if the number is negative. 
No bit flipping at the moment.
"""
import sys

def my_main():
    env_arg = sys.argv
    if len(env_arg) < 3:
        print("Run script in command and pass a valid decimal")
    else:
        try:
            inp = int(env_arg[2])
            command = str(env_arg[1])
            if (command == "-d"):
                # Convert from binary to decimal
                print("Binary code: {}".format(binary_to_decimal(inp)))
            elif (command == "-b") :
                #Convert from decimal to binary
                print("Result decimal : {}".format(covert_to_binary(inp)))
            else:
                print("Wrong command. You can either use -d or -b!")
                
        except Exception as error:
            print("An error has occurred! "+ str(error))


def covert_to_binary(inp):
    final_result = ""
    tracker = inp
    for i in range(8):
        result = int(tracker % 2)
        tracker = tracker/2
        final_result += str(result)
    return final_result[::-1]

def binary_to_decimal(inp):
    base = 1
    str_inp = str(inp)[::-1]
    decimal =0
    for i in range(len(str_inp)):
        res = base * int(str_inp[i])
        if res > 0:
            decimal += res
        base *= 2
    return decimal
    
    
if __name__ == "__main__":
    my_main()