Given a number n where n>0 calculate sum of all number which are divisible by 3 or 5 between 1 to n

SumNumbersDivisibleBy3Or5

  public static long calculateAP(long start, long totalNumber, long difference){
       return  (totalNumber*((2*start)+(totalNumber-1)*difference))/2;
    }

  //Time complexity O(1) and Space complexity O(1)
  public static long sumOfDivisbleOf30r5(int number){
        long totalNumberDivisibleby3=number/3;
        long totalNumberDivisibleby5 = number/5;
        long totalNumberDivisibleby15 = number/(3*5);
        return calculateAP(3,totalNumberDivisibleby3,3)
                +calculateAP(5,totalNumberDivisibleby5,5)
                -calculateAP(15,totalNumberDivisibleby15,15);
    }