Created
April 29, 2019 20:33
-
-
Save dfm/506d02a32f9981094ce289046c829fc9 to your computer and use it in GitHub Desktop.
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
import numpy as np | |
def esolve_markley(M, ecc): | |
M = M % (2*np.pi) | |
flip = M > np.pi | |
M[flip] = 2*np.pi - M[flip] | |
alpha = (3*np.pi + 1.6*(np.pi-np.abs(M))/(1+ecc) )/(np.pi - 6/np.pi) | |
d = 3*(1 - ecc) + alpha*ecc | |
r = 3*alpha*d * (d-1+ecc)*M + M**3 | |
q = 2*alpha*d*(1-ecc) - M**2 | |
w = (np.abs(r) + np.sqrt(q**3 + r**2))**(2/3) | |
E = (2*r*w/(w**2 + w*q + q**2) + M) / d | |
f_0 = E - ecc*np.sin(E) - M | |
f_1 = 1 - ecc*np.cos(E) | |
f_2 = ecc*np.sin(E) | |
f_3 = 1-f_1 | |
d_3 = -f_0/(f_1 - 0.5*f_0*f_2/f_1) | |
d_4 = -f_0/(f_1 + 0.5*d_3*f_2 + (d_3**2)*f_3/6) | |
E = E -f_0/(f_1 + 0.5*d_4*f_2 + d_4**2*f_3/6 - d_4**3*f_2/24) | |
E[flip] = 2*np.pi - E[flip] | |
return E |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment