Created
May 7, 2016 20:37
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#include <stdio.h> | |
#include <stdlib.h> | |
// This is a program for converting a binary image (little-endian) | |
// into a set of integers that indicate the position where the bit | |
// value changes. It is much faster than going through bit-by-bit. | |
int main(int argc, char *argv[]) | |
{ | |
static const int debruijn[32] = | |
{ | |
0, 1, 28, 2, 29, 14, 24, 3, 30, 22, 20, 15, 25, 17, 4, 8, | |
31, 27, 13, 23, 21, 19, 16, 7, 26, 12, 18, 6, 11, 5, 10, 9 | |
}; | |
unsigned int state = 0; | |
// loop through all the available words | |
for (int i = 0; i < argc-1; i++) | |
{ | |
unsigned int x = state ^ strtoul(argv[i+1], 0, 0); | |
if (x != 0) | |
{ | |
// gcc and clang will automatically optimize this to bwapl opcode | |
#ifdef WORDS_BIG_ENDIAN | |
x = (x >> 24) | (x << 24) | ((x >> 8) & 0xff00u) | ((x << 8) & 0xff0000u); | |
#endif | |
do | |
{ | |
// isolate the lowest set bit | |
unsigned int y = x & -x; | |
// use a de Bruijn sequence to find out what bit is set | |
int b = debruijn[(y * 0x077CB531u) >> 27]; | |
// set lower bits and invert | |
x = ~(x | (y - 1)); | |
// invert the state | |
state = ~state; | |
// add the current word offset | |
b += 32*i; | |
// output the result | |
printf("%d ", b); | |
} | |
while (x); | |
} | |
} | |
printf("\n"); | |
return 0; | |
} |
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