Demonstrate that the runtime type of a lambda expression depends on the order of execution of lambda expressions

LambdaExample.java

// Run this first with no args, then with 1 or more args
public class LambdaExample {
  public static void main(String[] args) {
    if(args.length > 0) {
      lambdaA();
      lambdaB();
    } else {
      lambdaB();
      lambdaA();
    }
  }

  private static void lambdaA() {
    Runnable runnable = () -> {};
    System.out.println("Lambda A class name: " + runnable.getClass().getName());
  }

  private static void lambdaB() {
    Runnable runnable = () -> {};
    System.out.println("Lambda B class name: " + runnable.getClass().getName());
  }
}

output-1-arg.txt

Lambda A class name: LambdaExample$$Lambda$168/0x000000080019e440
Lambda B class name: LambdaExample$$Lambda$169/0x000000080019a440

output-no-args.txt

Lambda B class name: LambdaExample$$Lambda$168/0x000000080019e440
Lambda A class name: LambdaExample$$Lambda$169/0x000000080019a440