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March 5, 2011 06:59
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Solution to UVa 11235 using Schieber-Vishkin algorithm
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#include <stdio.h> | |
#include <stdlib.h> | |
#include <limits.h> | |
#define forn(i,n) for(i=0; i<(n); i++) | |
#define forsn(i,s,n) for(i=(s); i<(n); i++) | |
#define MAXN 100001 | |
int N, A[MAXN], pi[MAXN], beta[MAXN], alfa[MAXN], tau[MAXN], lam[MAXN]; | |
struct node { | |
int child, sib, parent; | |
}; | |
#define CHILD(v) nodes[v].child | |
#define SIB(v) nodes[v].sib | |
#define PARENT(v) nodes[v].parent | |
void process(void) { | |
int u,v,p,h,n,t; | |
struct node *nodes = calloc(N+1,sizeof(*nodes)); | |
/* make triply linked tree */ | |
t = 0; | |
for(v=N; v>0; v--) { | |
u = 0; | |
while(A[v]>A[t] || (A[v]==A[t] && v>t)) { | |
u = t; | |
t = PARENT(t); | |
} | |
if(u) { | |
SIB(v) = SIB(u); | |
SIB(u) = 0; | |
PARENT(u) = v; | |
CHILD(v) = u; | |
} else | |
SIB(v) = CHILD(t); | |
CHILD(t) = v; | |
PARENT(v) = t; | |
t = v; | |
} | |
/* begin first traversal */ | |
p = CHILD(0); | |
n = 0; | |
lam[0] = -1; | |
s3: /* compute beta in the easy case */ | |
n++; | |
pi[p] = n; | |
tau[n] = 0; | |
lam[n] = 1+lam[n>>1]; | |
if(CHILD(p)) { | |
p = CHILD(p); | |
goto s3; | |
} | |
beta[p] = n; | |
s4: /* compute tau, bottom-up */ | |
tau[beta[p]] = PARENT(p); | |
if(SIB(p)) { | |
p = SIB(p); | |
goto s3; | |
} | |
p = PARENT(p); | |
/* compute beta in the hard case */ | |
if(p) { | |
h = lam[n & -pi[p]]; | |
beta[p] = ((n>>h)|1)<<h; | |
goto s4; | |
} | |
/* begin second traversal */ | |
p = CHILD(0); | |
lam[0] = lam[n]; | |
pi[0] = beta[0] = alfa[0] = 0; | |
s7: /* compute alfa, top-down */ | |
alfa[p] = alfa[PARENT(p)] | (beta[p] & -beta[p]); | |
if(CHILD(p)) { | |
p = CHILD(p); | |
goto s7; | |
} | |
s8: /* continue to traverse */ | |
if(SIB(p)) { | |
p = SIB(p); | |
goto s7; | |
} else { | |
p = PARENT(p); | |
if(p) goto s8; | |
} | |
free(nodes); | |
} | |
int nca(int x, int y) { | |
int h,k,j,l,z; | |
/* find common height */ | |
if(beta[x] <= beta[y]) | |
h = lam[beta[y] & -beta[x]]; | |
else | |
h = lam[beta[x] & -beta[y]]; | |
/* find true height */ | |
k = alfa[x] & alfa[y] & -(1<<h); | |
h = lam[k & -k]; | |
/* find beta[z] */ | |
j = ((beta[x] >> h)|1) << h; | |
/* find x' and y' */ | |
if(j != beta[x]) { | |
l = lam[alfa[x] & ((1<<h)-1)]; | |
x = tau[((beta[x] >> l)|1) << l]; | |
} | |
if(j != beta[y]) { | |
l = lam[alfa[y] & ((1<<h)-1)]; | |
y = tau[((beta[y] >> l)|1) << l]; | |
} | |
/* find z */ | |
z = (pi[x] <= pi[y]) ? x : y; | |
return z; | |
} | |
int max(int a, int b) { | |
return a > b ? a : b; | |
} | |
int main(void) { | |
int n,i,j,q,Q,x,y,oldx,count,z; | |
int R[MAXN],B[MAXN]; | |
for(;;) { | |
scanf("%d", &n); | |
if(!n) break; | |
scanf("%d", &Q); | |
A[0] = INT_MAX; | |
N=1, count=0; | |
forsn(i,1,n+1) { | |
scanf("%d", &x); | |
if(i>1 && x!=oldx) { | |
A[N] = count; | |
R[N] = i; | |
N++; | |
count = 0; | |
} | |
B[i] = N; | |
count++; | |
oldx = x; | |
} | |
A[N] = count; | |
R[N] = i; | |
process(); | |
forn(q,Q) { | |
scanf("%d%d", &i, &j); | |
x=B[i], y=B[j]; | |
if(x == y) { | |
z = j-i+1; | |
} else { | |
z = (x+1 != y) ? A[nca(x+1,y-1)] : 0; | |
z = max(z, max(R[x]-i, A[y]-R[y]+j+1)); | |
} | |
printf("%d\n", z); | |
} | |
} | |
return 0; | |
} |
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