handle IndexOutOfBoundsException using try catch Swift 3

Array IndexOutOfBoundsException

enum ArrayError: Error {
    case OutOfBounds(min: Int, max: Int)
}

extension Array {
    
    mutating func set(index:Int, value: Element) throws {
        
        
        guard self.indices.contains(index) else {
            throw ArrayError.OutOfBounds(min: 0, max: (self.count - 1))
        }
        
        self[index] = value
        
    }
    
    mutating func get(index:Int) throws -> Any {
        
        guard self.indices.contains(index) else {
            throw ArrayError.OutOfBounds(min: 0, max: (self.count - 1))
        }
        
        return self[index]
        
    }
    
}

var myArray : [Float] = [1,2]

do {
    try myArray.set(index: 1, value: Float(5))
} catch ArrayError.OutOfBounds(let min, let max) {
    print("out of bounds : \(min) => \(max)")
}

// throw exception
do {
    try myArray.get(index: 9)
} catch ArrayError.OutOfBounds(let min, let max) {
    print("out of bounds : \(min) => \(max)")
}