Common random ID strategy

common_id.ex

# Elixir
iex> chars = Enum.to_list(?a..?z)
iex> k = length(chars)
iex> common_id = fn n -> for(_ <- 1..n, do: :rand.uniform(k) - 1)
       |> Enum.map(&(chars |> Enum.at(&1)))
       |> List.to_string()
     end
iex> common_id.(8)
# => "qyyrpoco"

common_id.py

# Python
from random import randint
import string

chars = string.ascii_lowercase
n_chars = len(chars)
common_id = lambda len: "".join([chars[randint(0,n_chars)] for _ in range(len)])
common_id(8)
# => 'vbautjwb'

commonId.js

// JavaScript
const commonId = (n) => {
  const chars = 'abcdefghijklmnopqrstuvwxyz'
  let id = '';
  for (let i = 0; i < n; i++) {
    id += chars.charAt(Math.floor(Math.random() * chars.length));
  }
  return id
}
commonId(8)
// => 'btvjyxfe'

CommonId.swift

// Swift
let chars = (UInt8(ascii: "a")...UInt8(ascii: "z")).map { $0 }
func commonId(len: Int) -> String {
  String(bytes: (0..<len)
    .map { $0 }
    .map { _ in
      chars[Int.random(in: 0..<chars.count)]
    }, encoding: .ascii)!
}
commonId(len: 8)
// => "poqeumsd"