给出一个整型数字,返回代表该值的英文(0-1000)

6-8-list-new.py

# _*_coding:utf-8_*_
# !/usr/bin/env python
"""
给出一个整型数字，返回代表该值的英文
范围为[0, 1000）
思路：
首先判断是否是不规则读法；
其次考虑两位数读法；
而三位数读法为 n hundred and 两位数读法
"""

englishnum = {0: '', 1: 'one', 2: 'two', 3: 'three', 4: 'four', 5: 'five',
                  6: 'six', 7: 'seven', 8: 'eight', 9: 'nine', 10: 'ten',
                  11: 'eleven', 12: 'twelve', 13: 'thirteen', 14: 'fourteen',
                  15: 'fifteen', 16: 'sixteen', 17: "seventeen", 18: 'eighteen',
                  19: 'nineteen', 20: 'twenty', 30: 'thirty', 40: 'forty', 50:'fifty',
                  80: 'eighty', 100: 'one-hundred'}


def two_digit(number):
    """返回两位数的数字读法(不包括10-20)"""
    numberint = int(number)
    if 100 > numberint > 20:
        firstnum = int(number[0])
        lastnum = int(number[1])

        tens = firstnum * 10

        # 处理以0结尾的数字
        if lastnum != 0:
            if tens in englishnum:
                return '%s-%s' % (englishnum[tens], englishnum[lastnum])
            else:
                return '%sty-%s' % (englishnum[firstnum], englishnum[lastnum])
        else:
            # 处理以0为结尾的不规则数字
            if tens in englishnum:
                return englishnum[tens]
            else:
                return englishnum[firstnum] + 'ty'

    # 处理开头为0的两位数
    elif (len(number) == 2) & (numberint in englishnum):
        return englishnum[numberint]
    else:
        print 'not two digit'


def three_digit(number):
    """返回三位数的英文读法"""
    numberint = int(number)
    if 1000 > numberint >= 100:
        # 三位数的百位
        tfirstnum = numberint / 100
        engtfirstnum = englishnum[tfirstnum] + '-hundred'

        # 三位数剩余的十位和个位视为两位数用and连接
        restnum = number[1:3]
        engrestnum = two_digit(restnum)

        return '%s and %s' % (engtfirstnum, engrestnum)


def engnum(number):
    """返回0-1000的数字的英语读法"""

    numberint = int(number)
    length = len(number)

    # 检查不规则的英文读法的数字
    if numberint in englishnum:
        return englishnum[numberint]
    # 返回两位数的读法
    elif length == 2:
        return two_digit(number)
    # 返回三位数的读法
    elif length == 3:
        return three_digit(number)
    else:
        raise Exception('Error, the number may not in 0-1000')


def cli_english_num():
    """命令行界面"""
    while True:
        number = raw_input("please input number(0-1000): ")

        print '%s in english is %s' % (number, engnum(number))

        continuerun = raw_input("""
    ---------------------
    是否继续检查数字,
    [1]继续
    [0]退出

    请输入数字并以回车结束:
    ---------------------\n
        """)
        if continuerun == '0':
            break

cli_english_num()