Created
September 17, 2018 19:20
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Bellman-Ford algorithm for shortest paths
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import numpy as np | |
import numba | |
@numba.jit | |
def bellman_ford(graph, start_vertex): | |
n = len(graph.nodes) | |
A = np.zeros((n+1, n)) | |
A[0, :] = np.inf | |
A[0, start_vertex] = 0 | |
for i in range(1, n+1): | |
for v in range(n): | |
# convenient to store costs in a matrix for vectorization | |
new_path_costs = A[i-1, graph.incoming_neighbors[v]] +\ | |
graph.edge_costs[graph.incoming_neighbors[v], v] | |
A[i, v] = min(A[i-1, v], min(new_path_costs)) | |
# stopping early | |
if i < n-1 and (A[i, :] == A[i-1, :]).all(): | |
return A[i, :] | |
if (A[-2, :] == A[-1, :]).all(): | |
return A[n-1, :] | |
else: | |
raise ValueError('Negative cycle present') |
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