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@dmikurube
Created May 12, 2012 04:32
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RTTI
#include <iostream>
#include <typeinfo>
class Base {
public:
Base() : x_(0) {}
virtual void print() { std::cout << "Base" << std::endl; }
private:
int x_;
};
class Sub : public Base {
public:
Sub() : y_(0) {}
virtual void print() { std::cout << "Sub" << std::endl; }
private:
int y_;
};
class NoVirtualBase {
public:
NoVirtualBase() : z_(0) {}
void print() { std::cout << "NoVirtualBase" << std::endl; }
private:
int z_;
};
class NoVirtualSub: public NoVirtualBase {
public:
NoVirtualSub() : w_(0) {}
void print() { std::cout << "NoVirtualSub" << std::endl; }
private:
int w_;
};
int main() {
Base b;
Sub s;
Base* p = static_cast<Base*>(&s);
NoVirtualBase nb;
NoVirtualSub ns;
NoVirtualBase* np = static_cast<NoVirtualBase*>(&ns);
std::cout << typeid( b).name() << std::endl; // 4Base
std::cout << typeid( s).name() << std::endl; // 3Sub
std::cout << typeid( *p).name() << std::endl; // 3Sub
std::cout << typeid( nb).name() << std::endl; // 13NoVirtualBase
std::cout << typeid( ns).name() << std::endl; // 12NoVirtualSub
std::cout << typeid(*np).name() << std::endl; // 13NoVirtualBase <= It's not NoVirtualSub!
std::cout << typeid( &b).name() << std::endl; // P4Base
std::cout << typeid( &s).name() << std::endl; // P3Sub
std::cout << typeid( p).name() << std::endl; // P4Base
std::cout << typeid(&nb).name() << std::endl; // P13NoVirtualBase
std::cout << typeid(&ns).name() << std::endl; // P12NoVirtualSub
std::cout << typeid( np).name() << std::endl; // P13NoVirtualBase
void* vb = &b;
void* vs = &s;
void* vnb = &nb;
void* vns = &ns;
std::cout << typeid( vb).name() << std::endl; // Pv
std::cout << typeid( vs).name() << std::endl; // Pv
std::cout << typeid(vnb).name() << std::endl; // Pv
std::cout << typeid(vns).name() << std::endl; // Pv
return 0;
}
@dmikurube
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Please look at the line 51 for RTTI and vtables.

typeid() looks type of any "variable" in source code. But, runtime object type is only available in objects with vtables.

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