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@dmsurti
Created September 21, 2016 12:41
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Bartender initial solution (Gerard)
# yes = True
# y = True
# no = False
# n = False
questions = {
"strong": "Do ye like yer drinks strong?",
"salty": "Do ye like it with a salty tang?",
"bitter": "Are ye a lubber who likes it bitter?",
"sweet": "Would ye like a bit of sweetness with yer poison?",
"fruity": "Are ye one for a fruity finish?",
}
Preferences = {}
ingredients = {
"strong": ["glug of rum", "slug of whisky", "splash of gin"],
"salty": ["olive on a stick", "salt-dusted rim", "rasher of bacon"],
"bitter": ["shake of bitters", "splash of tonic", "twist of lemon peel"],
"sweet": ["sugar cube", "spoonful of honey", "spash of cola"],
"fruity": ["slice of orange", "dash of cassis", "cherry on top"],
}
def Bartender (yes,y,no,n):
"""You tell me what you like, I make it!"""
print("I'm a function. My name is {}".format(Bartender.__name__))
print("I'm a bit slow, I only accept yes or no answers")
print("{}". format(questions['strong']))
input("answer")
if "answer" == True:
Preferences['strong'] = 1
print("{}". format(questions['salty']))
input ("")
print("{}". format(questions['bitter']))
input ("")
print("{}". format(questions['sweet']))
input ("")
print("{}". format(questions['fruity']))
input ("")
if __name__ == '__main__':
Bartender (yes,y,no,n)
@dmsurti
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dmsurti commented Sep 21, 2016

if "answer" == True:
        Preferences['strong'] = 1
  • Won't the user enter yes, y, no, n for an answer, IIRC. Then you should be comparing answering with that.
  • Also, you can store Booleans in a dictionary. So that makes it evident that preferences['strong'] = 1 has a simpler solution.

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