dnamsons

#include <iostream>
using namespace std;

int main() {
  string ievade;
  cin >> ievade;
  int length = ievade.length(); 

  if(length <= 100) {
    for(int i = 0; i < length; i++) {

dnamsons

{
    "name": "Debug Current File",
    "type": "Ruby",
    "request": "launch",
    "cwd": "${workspaceRoot}",
    "program": "${file}",
    "env": {
        "pathToRDebugIDE": "/Users/namsodav/.rvm/gems/ruby-2.4.4/bin/rdebug-ide"
    }
},

dnamsons

function prompt_rvm {
    rbv=`rvm-prompt`
    echo [$rbv]
}

function parse_git_branch {
    git branch 2> /dev/null | sed -e '/^[^*]/d' -e 's/* \(.*\)/(\1)/'
}

# user in blue@directory name in green[ruby version in red](current git branch in brown)

dnamsons

General
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dnamsons

class Spiral
  attr_accessor :array, :result, :upper_limit, :bottom_limit, :right_limit, :left_limit
  
  def initialize(array)
    @array = array
  end

  def order
    @upper_limit = 0
    @bottom_limit = @array.length - 1

dnamsons

Keybase proof

I hereby claim:

• I am dnamsons on github.
• I am dnamsons (https://keybase.io/dnamsons) on keybase.
• I have a public key ASC8nDOONn7dqE_KV1-XWC4XiVvmQeCYlmqT0fDBQZoQ6Ao

To claim this, I am signing this object:

dnamsons

#include <iostream>
#include <list>
using namespace std;

//Funkcija pārvieto pieprasīto elementu uz saraksta beigām
void do_move(list<int> &l, int n)
{
    
    list<int>::iterator iter = l.begin();
    for (int index = 0; index != n; ++iter, index++)

dnamsons

#include <iostream>
using namespace std;

/*
====================================================================
Dāvis Namsons stud. apl. nr. - dn17005
====================================================================
G6. Uzrakstīt funkciju, kas no diviem sarakstiem izveido trešo tā,
lai 3. sarakstā būtu visas vērtības no 1. un 2. saraksta
un izveidotajā sarakstā nebūtu elementu ar vienādām vērtībām.

dnamsons

#include <iostream>
#include <fstream>
using namespace std;


int main()
{
    fstream fin;
    fstream fout;
    fin.open("cd.in",fstream::in);