Square Root - iterative according to Heron

sqrt-heron.cpp

#include <iostream>
using namespace std;

int main()
{
  int x = 10;

  double a = 1.0 * x;
  double l = 1.0;
  const double eps = 0.000001;
  int iter = 0;

  while ((a - l) > eps)
  {
    a = (l + a) / 2.0;
    l = x / a;
    iter++;
  }

  cout << "SQRT(" << x << ") = " << l << " - " << iter << " iterations" << endl;
  cout << "Check: l^2 = " << l * l << endl;
  return 0;
}