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@dotZak
Created October 14, 2015 10:43
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PHP: Return string of origin year to the current year
function origin_year_to_current_year( $origin_year, $sep = '-', $after = '' )
{
$date_range = $origin_year;
if( date('Y') != $origin_year )
{
$current_year = date('Y');
$date_range = $current_year . $sep . date('Y');
}
$return = $date_range . $after;
return $return;
}
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