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@douglasmiranda
Created September 21, 2011 15:05
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Get latest videos from Youtube with Jquery (Gdata API)
function show_my_videos(data){
html = ['<ul id="youtube-videos">'];
$(data.feed.entry).each(function(entry){
url = this.link[0].href;
url_thumbnail = this.media$group.media$thumbnail[3].url;
description = this.media$group.media$description.$t;
html.push('<li><a href="'+url+'">');
html.push('<img src="'+url_thumbnail+'" alt="'+description+'">');
html.push('</a></li>');
});
html.push('</ul>');
$("#videos").html(html.join(''));
}
$.ajax({
type: "GET",
url: "http://gdata.youtube.com/feeds/users/[YOUTUBE_USER]/uploads?alt=json-in-script&format=5",
cache: false,
dataType:'jsonp',
success: function(data){
show_my_videos(data);
//If you want to see in console...
// console.log(data);
// console.log(data.feed.entry);
// $(data.feed.entry).each(function(){
// console.log(this.link[0].href);
// console.log(this.media$group.media$thumbnail[3].url);
// console.log(this.media$group.media$description.$t);
// });
}
});
<!DOCTYPE HTML>
<html lang="en-US">
<head>
<meta charset="UTF-8">
<title>Latest Youtube Videos</title>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.2.6/jquery.js"></script>
<script src="get-latest-videos.js"></script>
</head>
<body>
<div id="videos"> <!-- here will be loaded your videos --> </div>
</body>
</html>
@gweatherson
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This is great, thank you. How do I go about limiting the output to only 3 videos?

@jtrollia
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Just add "&max-results=3" to your url o/

@gracehcoote
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Hi there, I was wondering if there was a way to choose a specific video with this rather than just the latest one?

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ghost commented Oct 3, 2014

It Won't work here

@rodoaravena
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This solution not work anymore, gdata api is deprecated

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