Created
January 5, 2018 21:57
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Implementation of an integer min heap in Python3, O(n*log(n)) time.
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# TODO: Should make this an object for sharing. | |
heap = [] | |
def hasParent(index): | |
return parentIndex(index) >= 0 and parentIndex(index) < len(heap) | |
def hasLeftChild(index): | |
return leftChildIndex(index) < len(heap) | |
def hasRightChild(index): | |
return rightChildIndex(index) < len(heap) | |
def parent(index): return heap[parentIndex(index)] | |
def leftChild(index): return heap[leftChildIndex(index)] | |
def rightChild(index): return heap[rightChildIndex(index)] | |
def parentIndex(index): return (index-1)//2 | |
def leftChildIndex(index): return (index*2)+1 | |
def rightChildIndex(index): return (index*2)+2 | |
def value(index): | |
if index > len(heap): raise "Index off bounds of heap!" | |
return heap[index]; | |
def add(value): | |
heap.append(value) | |
heapifyUp() | |
def remove(value): | |
index = heap.index(value) | |
heap[index] = heap[len(heap)-1] | |
heap.remove(heap[len(heap)-1]) | |
heapifyDown(index) | |
def min(): | |
if len(heap) == 0: raise "Nothing in the heap!" | |
return heap[0] | |
def swap(indexOne, indexTwo): | |
temp = heap[indexOne] | |
heap[indexOne] = heap[indexTwo] | |
heap[indexTwo] = temp | |
def heapifyDown(index): | |
if len(heap) == 0: return | |
currentIndex = index | |
while (hasLeftChild(currentIndex)): | |
minNodeIndex = leftChildIndex(currentIndex) | |
if hasRightChild(currentIndex) and rightChild(currentIndex) < leftChild(currentIndex): | |
minNodeIndex = rightChildIndex(currentIndex) | |
if minNodeIndex < value(currentIndex): | |
swap(currentIndex, minNodeIndex) | |
currentIndex = minNodeIndex | |
else: | |
break | |
def heapifyUp(): | |
if len(heap) == 0: return | |
currentIndex = len(heap)-1 | |
while hasParent(currentIndex): | |
if value(currentIndex) > parent(currentIndex): break; | |
swap(currentIndex, parentIndex(currentIndex)) | |
currentIndex = parentIndex(currentIndex) | |
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