Bash script I wrote to find out unused images in a sass project (assuming that all images are in the "img" directory and sass files in the "sass" directory).

gistfile1.ps1

#!/bin/bash

cd img
images=(`ls *.png *.jpg *.jpeg *.gif 2> /dev/null`) # get all images
cd ../sass
scss=(`ls *.scss */*.scss`) # get all compass files

usedImg=()
unusedImg=()

for i in "${images[@]}"; do  # for each image...
	:
	used="not-used"
	for f in "${scss[@]}" ; do # for each compass file...
		:
		rule=`cat $f | grep $i` # find out if images is used in any rule

		if  [ "$rule" ] ; then # if so, add it to the "used images" array
			usedImg=("${usedImg[@]}" "$f \t\t\t\t$i\n")
			used=""
			break
		fi
	done
	if [ $used ] ; then # not found in any file: add it to the "unused images" array
		unusedImg=("${unusedImg[@]}" "$i")
	fi
done

# print used and unused images 
echo "Used images:"
echo -e "${usedImg[@]}"
echo
echo "Unused images, moving them to _unused:"
echo "${unusedImg[@]}" 

# move all unused images to another directory
cd ../img
mkdir _unused 2> /dev/null
for i in "${unusedImg[@]}"; do 
	:
	mv $i ./_unused
done