A method creating a single collector given a list of collectors, see https://stackoverflow.com/a/32072206/1833472 "groupingBy with multiple Collectors"

MultiCollectors.java

  @SuppressWarnings({"null", "unchecked"})
    public static <V, R> Collector<V, ?, List<R>> combine(List<Collector<V, ?, R>> collectors) {
    
        final Supplier<List<Object>> supplier = () -> collectors.stream().map(Collector::supplier)
                .map(Supplier::get).collect(Collectors.toList());
    
        final BiConsumer<List<Object>, V> biConsumer = (List<Object> list, V e) -> IntStream.range(0, collectors.size())//
                .forEach(i -> ((BiConsumer<Object, V>) collectors.get(i).accumulator()).accept(list.get(i), e));
    
        final BinaryOperator<List<Object>> binaryOperator = (List<Object> l1, List<Object> l2) -> {
            IntStream.range(0, collectors.size()).forEach(
                    i -> l1.set(i, ((BinaryOperator<Object>) collectors.get(i).combiner()).apply(l1.get(i), l2.get(i))));
            return l1;
        };
    
        Function<List<Object>, List<R>> function = (List<Object> list) -> 
        IntStream.range(0, collectors.size()).mapToObj(
                i ->((Function<Object, R>) collectors.get(i).finisher()).apply(list.get(i))).collect(Collectors.toList());
    
        return Collector.of( supplier, biConsumer, binaryOperator, function);
    }