Created
December 20, 2016 06:46
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A simple algorithm for traversing a binary search tree in-order without using recursion.
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function traverseTreeInOrder(tree) { | |
// In the real world, we'd need a more robust solution of storing | |
// and looking up object IDs. But JavaScript doesn't make that easy. | |
const visitedNodes = {}; | |
const stack = [ tree ]; | |
while (stack.length > 0) { | |
let node = stack.pop(); | |
if (!node) { | |
continue; | |
} | |
if (!visitedNodes[node.id]) { | |
stack.push(node.right); | |
stack.push(node); | |
stack.push(node.left); | |
visitedNodes[node.id] = true; | |
} else { | |
visitNode(node); | |
} | |
} | |
} | |
function visitNode(node) { | |
console.log(node.id); | |
} | |
const SampleTree = { | |
id: 7, | |
left: { | |
id: 4, | |
left: { | |
id: 2, | |
left: { id: 1 }, | |
right: { id: 3 } | |
}, | |
right: { | |
id: 6, | |
left: { id: 5 } | |
} | |
}, | |
right: { | |
id: 8, | |
right: { | |
id: 10, | |
left: { id: 9 }, | |
right: { | |
id: 11, | |
right: { id: 12 } | |
} | |
} | |
} | |
}; | |
traverseTreeInOrder(SampleTree); |
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