FizzBuzz in Swift using pattern matching

fizzbuzz.swift

func fizzbuzz(i: Int) -> String {
    let result = (i % 3, i % 5)
    switch result {
    case (0, _):
        return "Fizz"
    case (_, 0):
        return "Buzz"
    case (0, 0):
        return "FizzBuzz"
    default:
        return "\(i)"
    }
}

for number in 1...100 {
    println(fizzbuzz(number))
}

Nice, I like the functional style.

Reminds me of scala http://rosettacode.org/wiki/FizzBuzz#Idiomatic_scala_code

Actually, the idiomatic Scala version's pattern matching works in Swift practically unchanged:

func fizzbuzz(i: Int) -> String {
    switch (i % 3, i % 5) {
        case (0, 0):
            return "FizzBuzz"
        case (0, _):
            return "Fizz"
        case (_, 0):
            return "Buzz"
        default:
            return "\(i)"
    }
}

Also, while Swift's Range doesn't come with a foreach method like Scala's, it's easy enough to define one as an extension:

extension Range {
    func foreach(f: T -> ()) -> () {
        for x in self {
            f(x)
        }
    }
}

(1...100).foreach({
    println(fizzbuzz($0))
})

Really, the only thing missing from Swift that's present in the Scala version is Scala's implicit return values for all code blocks.

Just as a note... dstaley's answer is incorrect.