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dustintheweb/debug-ajax-console.js

Created April 13, 2015 12:03
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Javascript to debug an ajax request
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debug-ajax-console.js
var oXhr;
oXhr = new XMLHttpRequest();
oXhr.id = (new Date()).getTime();
oXhr.onreadystatechange = function() {
if (oXhr.readyState === 4 && (oXhr.status === 200)) {
// code stuffs
console.log(this.id);
}
};
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