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@eagleon
Created June 17, 2012 04:10
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JSON相关东东
var json = $.parseJSON(data); //jquery直接支持
var json = JSON.parse(data); //jquery直接支持
var json = eval ("(" + data + ")");
@eagleon
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eagleon commented Jun 17, 2012

//JSON各端数据形式:
//{"errmsg":"SUCCESS","imgurl":"/Java_Web/upload/temp/20120617/20120617144831_4213","errcode":"000"} 正确服务端打印输出
//{"errmsg":"SUCCESS","imgurl":/Java_Web/upload/temp/20120617/20120617145157_4537,"errcode":"000"} 错误服务端打印输出,小心!!

//"{"errmsg":"SUCCESS","imgurl":"/Java_Web/upload/temp/20120617/20120617145038_8681","errcode":"000"}\r\n" 正确浏览器端得到数据
//"{"errmsg":"SUCCESS","imgurl":/Java_Web/upload/temp/20120617/20120617145157_4537,"errcode":"000"}\r\n" 错误浏览器端得到数据

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