eamonm95/.block

## .block
license: mit

## README.md

      
    Raw
  

              README.md
            
          
    Built with blockbuilder.org
forked from scresawn's block: Sample problems: objects and arrays
forked from scresawn's block: Sample problems 2: objects and arrays

  
## index.html
<!DOCTYPE html>
<head>
  <meta charset="utf-8">
  <script src="https://d3js.org/d3.v4.min.js"></script>
  <style>
    body { margin:0;position:fixed;top:0;right:0;bottom:0;left:0; }
  </style>
</head>

<body>
  <h1>Please look in the code below for 4 JavaScript practice problems.</h1>
  <p>(These problems don't include any SVG manipulation, so you will need to open the developer console in order to see the output of your code)</p>
  <script>
  // Problem 1: search array1 for those states whose location is "East"
  // using console.log(), print just the state name(s).

  array1 = [
    				{name: "Arizona",  location: "Southwest"},
           	{name: "Virginia", location: "East"},
            {name: "Florida",  location: "Southeast"}
           ];
array1.forEach(function(d){
  if(d.location == "East"){
    //console.log(d.name)
  }
})
  // Problem 2: search array1 (above) for those states whose location contains the substring "South"
  // using console.log(), print just the state name(s) for these states.
    array1.forEach(function(d){
  if(d.location.includes("South")){
    //console.log(d.name)
  }
})
  // Problem 3: using iteration and console.log(), print those items that are in
  // array2 but NOT in array3

  array2 = ['a','b','c', 65, 'd'];
  array3 = ['a','c','e','f','g', 87];
  array2.forEach(function(a2){
    if(array3.includes(a2)){
    }
    else{
      //console.log(a2)
    }
  })
  // Problem 3: 'states' is an array of objects. Sort the array in ascending order
  // by state name

  states = [{name: "Alaska", id: "AK", population: 741894},
            {name: "Virginia", id: "VA", population: 8411808},
    				{name: "Arizona", id: "AZ", population: 6931071},
            {name: "Florida", id: "FL", population: 20984400}]

  states.sort(function(a, b){
        var x = a.name.toLowerCase();
        var y = b.name.toLowerCase();
        if (x < y) {return -1;}
        if (x > y) {return 1;}
        return 0;
    });
   //console.log(states)
  // Problem 4: write code that determines which state(s) have a population value that is an even number. Print out the state(s) to the console
	states.forEach(function(d){
    if(d.population%2 == 0){
      //console.log(d.name)
    }
  })


  </script>
</body>
	<!DOCTYPE html>
	<head>
	<meta charset="utf-8">
	<script src="https://d3js.org/d3.v4.min.js"></script>
	<style>
	body { margin:0;position:fixed;top:0;right:0;bottom:0;left:0; }
	</style>
	</head>

	<body>
	<h1>Please look in the code below for 4 JavaScript practice problems.</h1>
	<p>(These problems don't include any SVG manipulation, so you will need to open the developer console in order to see the output of your code)</p>
	<script>
	// Problem 1: search array1 for those states whose location is "East"
	// using console.log(), print just the state name(s).

	array1 = [
	{name: "Arizona", location: "Southwest"},
	{name: "Virginia", location: "East"},
	{name: "Florida", location: "Southeast"}
	];
	array1.forEach(function(d){
	if(d.location == "East"){
	//console.log(d.name)
	}
	})
	// Problem 2: search array1 (above) for those states whose location contains the substring "South"
	// using console.log(), print just the state name(s) for these states.
	array1.forEach(function(d){
	if(d.location.includes("South")){
	//console.log(d.name)
	}
	})
	// Problem 3: using iteration and console.log(), print those items that are in
	// array2 but NOT in array3

	array2 = ['a','b','c', 65, 'd'];
	array3 = ['a','c','e','f','g', 87];
	array2.forEach(function(a2){
	if(array3.includes(a2)){
	}
	else{
	//console.log(a2)
	}
	})
	// Problem 3: 'states' is an array of objects. Sort the array in ascending order
	// by state name

	states = [{name: "Alaska", id: "AK", population: 741894},
	{name: "Virginia", id: "VA", population: 8411808},
	{name: "Arizona", id: "AZ", population: 6931071},
	{name: "Florida", id: "FL", population: 20984400}]

	states.sort(function(a, b){
	var x = a.name.toLowerCase();
	var y = b.name.toLowerCase();
	if (x < y) {return -1;}
	if (x > y) {return 1;}
	return 0;
	});
	//console.log(states)
	// Problem 4: write code that determines which state(s) have a population value that is an even number. Print out the state(s) to the console
	states.forEach(function(d){
	if(d.population%2 == 0){
	//console.log(d.name)
	}
	})



	</script>
	</body>