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Python's 'if' statement gets privileged information from conditionals
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# python 'if' statement is priviliged to the boolean output of compound conditionals | |
# other statements are not, and have to double-evaluate the output | |
# unless the output is "the last one" | |
class X: | |
def __init__(self): | |
self.v = False | |
self.c = 0 | |
def __bool__(self): | |
self.c = self.c + 1 | |
print("boolin'", self.c) | |
self.v = not self.v | |
return self.v | |
y = 1 | |
n = 0 | |
# case 1: 'if' gets a bool back from "or" | |
x = X() | |
if x or y: | |
assert x.c == 1 | |
else: | |
# we never get here, because if doesnt' need to reevaluate x | |
assert False | |
# case 2: looks like the same code as above, but z isn't priviliged like 'if' | |
x = X() | |
z = x or y | |
if z: | |
assert False | |
else: | |
# we had to bool twice... | |
assert x.c == 2 | |
# case 3: 'not' is not priviliged, like 'if; | |
x = X() | |
z = not(x or y) | |
if z: | |
assert x.c == 2 | |
else: | |
assert False | |
# case 4: we don't need to double-evaluate this | |
x = X() | |
z = n or x | |
if z: | |
assert x.c == 1 | |
else: | |
assert False | |
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