Eric Carlson ecarlson1201

## Static React Client
Gift List
https://github.com/ecarlson1201/gift-list-client

## IMG_1048.jpg

      
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                ecarlson1201
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              Last active
              November 28, 2018 06:51
            
              
                node-capstone-wireframe-user-stories
              
          
## gist:1199c62257b96fd87773e5de7e3ae02d
Get All
db.restaurants.find()

Limit and Sort
db.restaurants.find().sort({name: 1}).limit(10)

Get by Value
db.restaurants.find({borough: "Queens"})

Count

## gist:f3afd2bf6ef6e64b8b98ddb187bed64a
https://glitch.com/edit/#!/weak-capybara?path=server.js:47:0

## gist:14cb1375fdac820be8056f95256825dd
https://glitch.com/edit/#!/same-forgery?path=server.js:10:3

https://glitch.com/edit/#!/quark-limit?path=server.js:34:0

## IMG_1022.jpg

      
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                ecarlson1201
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              Created
              October 7, 2018 21:04
            
              
                API wireframes
              
          
## gist:edc2ab79c27e212666e6a3bf95a7e959
Help users with coding by providing basic information, how-to videos, links to discussion forums, and exercises about a searched topic.

## Shopping List app
https://repl.it/@EricCarlson1/Shopping-list-app-jQuery-1

## Cat Carousel
// https://repl.it/@EricCarlson1/Cat-carousel-jQuery

## Analysis
/* After removing any falsey items from the raw text using the getTokens function, we are left with one clean
lower case string containing only words seperated by spaces. The mostFrequentWord function takes that string
and assigns it to a variable, words. The function then iterates through each word and if it encounters a new
word it adds one to a new key in an object, wordFrequencies. If it has already encountered the word, it adds
one to the key at which it first encountered the word.

Afterwards, it sets a variable, currentMaxKey, to the first word in the wordFrequencies object and another
variable, currentMaxCount, to whatever index of the currentMaxKey in the wordFrequencies object.

Next the function iterates over every property in the wordFrequencies object. It then runs an if statement
	Get All
	db.restaurants.find()

	Limit and Sort
	db.restaurants.find().sort({name: 1}).limit(10)

	Get by Value
	db.restaurants.find({borough: "Queens"})

	Count
	https://glitch.com/edit/#!/same-forgery?path=server.js:10:3

	https://glitch.com/edit/#!/quark-limit?path=server.js:34:0
	/* After removing any falsey items from the raw text using the getTokens function, we are left with one clean
	lower case string containing only words seperated by spaces. The mostFrequentWord function takes that string
	and assigns it to a variable, words. The function then iterates through each word and if it encounters a new
	word it adds one to a new key in an object, wordFrequencies. If it has already encountered the word, it adds
	one to the key at which it first encountered the word.

	Afterwards, it sets a variable, currentMaxKey, to the first word in the wordFrequencies object and another
	variable, currentMaxCount, to whatever index of the currentMaxKey in the wordFrequencies object.

	Next the function iterates over every property in the wordFrequencies object. It then runs an if statement