Euler problem 6

problem6.py

#!/usr/bin/python
"""
The sum of the squares of the first ten natural numbers is,

1^2 + 2^2 + ... + 10^2 = 385
The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)^2 = 55^2 = 3025
Hence the difference between the sum of the squares of the first ten natural
numbers and the square of the sum is 3025 - 385 = 2640.

Find the difference between the sum of the squares of the first one hundred
natural numbers and the square of the sum.
"""

square = lambda x: x*x
sum_square = lambda m: sum(map(square, xrange(m+1)))
square_sum = lambda m: square(sum(xrange(m+1)))
difference = lambda m: square_sum(m) - sum_square(m)

print difference(100)